0=9x^2-256

Solution for 0=9x^2-256 equation:

0=9x^2-256

We move all terms to the left:

0-(9x^2-256)=0

We add all the numbers together, and all the variables

-(9x^2-256)=0

We get rid of parentheses

-9x^2+256=0

a = -9; b = 0; c = +256;
Δ = b2-4ac
Δ = 02-4·(-9)·256
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*-9}=\frac{-96}{-18}
=5+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*-9}=\frac{96}{-18}
=-5+1/3
$